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11320121233 = 76071488119
BaseRepresentation
bin10101000101011101…
…10101011110010001
31002012220210202000101
422202232311132101
5141140422334413
65111141252401
7550344304621
oct124256653621
932186722011
1011320121233
114889a056a3
12223b104101
1310b534bab5
14795600881
15463c24edd
hex2a2bb5791

11320121233 has 4 divisors (see below), whose sum is σ = 11321616960. Its totient is φ = 11318625508.

The previous prime is 11320121227. The next prime is 11320121237. The reversal of 11320121233 is 33212102311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11320121233 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11320121233.

It is not an unprimeable number, because it can be changed into a prime (11320121237) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 736453 + ... + 751666.

It is an arithmetic number, because the mean of its divisors is an integer number (2830404240).

Almost surely, 211320121233 is an apocalyptic number.

It is an amenable number.

11320121233 is a deficient number, since it is larger than the sum of its proper divisors (1495727).

11320121233 is an equidigital number, since it uses as much as digits as its factorization.

11320121233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1495726.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 11320121233 its reverse (33212102311), we get a palindrome (44532223544).

The spelling of 11320121233 in words is "eleven billion, three hundred twenty million, one hundred twenty-one thousand, two hundred thirty-three".

Divisors: 1 7607 1488119 11320121233