Base | Representation |
---|---|
bin | 110100101101101010… |
… | …0011000101001101001 |
3 | 101211012012001210221020 |
4 | 1221123110120221221 |
5 | 3323314003021301 |
6 | 124000503003053 |
7 | 11115142331646 |
oct | 1513324305151 |
9 | 354165053836 |
10 | 113201220201 |
11 | 44010157243 |
12 | 19b32a39489 |
13 | a8a07a4c44 |
14 | 569c408dcd |
15 | 2e28187436 |
hex | 1a5b518a69 |
113201220201 has 4 divisors (see below), whose sum is σ = 150934960272. Its totient is φ = 75467480132.
The previous prime is 113201220199. The next prime is 113201220241. The reversal of 113201220201 is 102022102311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 113201220201 - 21 = 113201220199 is a prime.
It is not an unprimeable number, because it can be changed into a prime (113201220241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18866870031 + ... + 18866870036.
It is an arithmetic number, because the mean of its divisors is an integer number (37733740068).
Almost surely, 2113201220201 is an apocalyptic number.
It is an amenable number.
113201220201 is a deficient number, since it is larger than the sum of its proper divisors (37733740071).
113201220201 is an equidigital number, since it uses as much as digits as its factorization.
113201220201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37733740070.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 113201220201 its reverse (102022102311), we get a palindrome (215223322512).
The spelling of 113201220201 in words is "one hundred thirteen billion, two hundred one million, two hundred twenty thousand, two hundred one".
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