Search a number
-
+
11320131401 = 48795324391
BaseRepresentation
bin10101000101011101…
…10111111101001001
31002012220211020221222
422202232313331021
5141140423201101
65111141411425
7550344346355
oct124256677511
932186736858
1011320131401
114889a122a7
12223b109b75
1310b5353607
14795604465
15463c2801b
hex2a2bb7f49

11320131401 has 8 divisors (see below), whose sum is σ = 11355744384. Its totient is φ = 11284570080.

The previous prime is 11320131397. The next prime is 11320131419. The reversal of 11320131401 is 10413102311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11320131401 - 22 = 11320131397 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 11320131401.

It is not an unprimeable number, because it can be changed into a prime (11320131481) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 451916 + ... + 476306.

It is an arithmetic number, because the mean of its divisors is an integer number (1419468048).

Almost surely, 211320131401 is an apocalyptic number.

It is an amenable number.

11320131401 is a deficient number, since it is larger than the sum of its proper divisors (35612983).

11320131401 is an equidigital number, since it uses as much as digits as its factorization.

11320131401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25831.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 11320131401 its reverse (10413102311), we get a palindrome (21733233712).

The spelling of 11320131401 in words is "eleven billion, three hundred twenty million, one hundred thirty-one thousand, four hundred one".

Divisors: 1 487 953 24391 464111 11878417 23244623 11320131401