Base | Representation |
---|---|
bin | 10101000101011101… |
… | …10111111101001011 |
3 | 1002012220211020222001 |
4 | 22202232313331023 |
5 | 141140423201103 |
6 | 5111141411431 |
7 | 550344346360 |
oct | 124256677513 |
9 | 32186736861 |
10 | 11320131403 |
11 | 4889a122a9 |
12 | 223b109b77 |
13 | 10b5353609 |
14 | 795604467 |
15 | 463c2801d |
hex | 2a2bb7f4b |
11320131403 has 8 divisors (see below), whose sum is σ = 12954122720. Its totient is φ = 9690347520.
The previous prime is 11320131397. The next prime is 11320131419. The reversal of 11320131403 is 30413102311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11320131403 - 213 = 11320123211 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11320131203) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1046088 + ... + 1056853.
It is an arithmetic number, because the mean of its divisors is an integer number (1619265340).
Almost surely, 211320131403 is an apocalyptic number.
11320131403 is a deficient number, since it is larger than the sum of its proper divisors (1633991317).
11320131403 is an equidigital number, since it uses as much as digits as its factorization.
11320131403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2103717.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 11320131403 its reverse (30413102311), we get a palindrome (41733233714).
The spelling of 11320131403 in words is "eleven billion, three hundred twenty million, one hundred thirty-one thousand, four hundred three".
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