1132014113 has 4 divisors (see below), whose sum is σ = 1132805508. Its totient is φ = 1131222720.

The previous prime is 1132014109. The next prime is 1132014157. The reversal of 1132014113 is 3114102311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3114102311 = 1049 ⋅2968639.

It can be written as a sum of positive squares in 2 ways, for example, as 968890129 + 163123984 = 31127^2 + 12772^2 .

It is a cyclic number.

It is not a de Polignac number, because 1132014113 - 2² = 1132014109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1132014091 and 1132014100.

It is not an unprimeable number, because it can be changed into a prime (1132016113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 393548 + ... + 396413.

It is an arithmetic number, because the mean of its divisors is an integer number (283201377).

Almost surely, 2^1132014113 is an apocalyptic number.

It is an amenable number.

1132014113 is a deficient number, since it is larger than the sum of its proper divisors (791395).

1132014113 is an equidigital number, since it uses as much as digits as its factorization.

1132014113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 791394.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 1132014113 is about 33645.4174145603. The cubic root of 1132014113 is about 1042.1989079622.

Adding to 1132014113 its reverse (3114102311), we get a palindrome (4246116424).

The spelling of 1132014113 in words is "one billion, one hundred thirty-two million, fourteen thousand, one hundred thirteen".