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11320543434145 = 511238949046193
BaseRepresentation
bin1010010010111100010011…
…1110000101010110100001
31111002020022010200021210211
42210233010332011112201
52440433433104343040
640024330313454121
72245611422340001
oct244570476052641
944066263607724
1011320543434145
113675019708360
121329bb7111341
136416a43ac34a
142b1cbac20001
1514971767b8ea
hexa4bc4f855a1

11320543434145 has 16 divisors (see below), whose sum is σ = 15463951823232. Its totient is φ = 7875160648960.

The previous prime is 11320543434131. The next prime is 11320543434199. The reversal of 11320543434145 is 54143434502311.

It is not a de Polignac number, because 11320543434145 - 25 = 11320543434113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11320543434098 and 11320543434107.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4474521832 + ... + 4474524361.

It is an arithmetic number, because the mean of its divisors is an integer number (966496988952).

Almost surely, 211320543434145 is an apocalyptic number.

It is an amenable number.

11320543434145 is a deficient number, since it is larger than the sum of its proper divisors (4143408389087).

11320543434145 is a wasteful number, since it uses less digits than its factorization.

11320543434145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8949046232.

The product of its (nonzero) digits is 345600, while the sum is 40.

Adding to 11320543434145 its reverse (54143434502311), we get a palindrome (65463977936456).

The spelling of 11320543434145 in words is "eleven trillion, three hundred twenty billion, five hundred forty-three million, four hundred thirty-four thousand, one hundred forty-five".

Divisors: 1 5 11 23 55 115 253 1265 8949046193 44745230965 98439508123 205828062439 492197540615 1029140312195 2264108686829 11320543434145