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11321000331 = 33773666777
BaseRepresentation
bin10101000101100100…
…01100000110001011
31002012222110101220120
422202302030012023
5141141134002311
65111212154323
7550354625604
oct124262140613
932188411816
1011321000331
11488a456123
12223b4689a3
1310b5598c84
1479578cdab
15463d4a706
hex2a2c8c18b

11321000331 has 4 divisors (see below), whose sum is σ = 15094667112. Its totient is φ = 7547333552.

The previous prime is 11321000293. The next prime is 11321000333. The reversal of 11321000331 is 13300012311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11321000331 - 213 = 11320992139 is a prime.

It is a super-2 number, since 2×113210003312 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11321000331.

It is not an unprimeable number, because it can be changed into a prime (11321000333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1886833386 + ... + 1886833391.

It is an arithmetic number, because the mean of its divisors is an integer number (3773666778).

Almost surely, 211321000331 is an apocalyptic number.

11321000331 is a deficient number, since it is larger than the sum of its proper divisors (3773666781).

11321000331 is an equidigital number, since it uses as much as digits as its factorization.

11321000331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3773666780.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 11321000331 its reverse (13300012311), we get a palindrome (24621012642).

The spelling of 11321000331 in words is "eleven billion, three hundred twenty-one million, three hundred thirty-one", and thus it is an aban number.

Divisors: 1 3 3773666777 11321000331