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11322063131 = 76914723099
BaseRepresentation
bin10101000101101100…
…01111100100011011
31002020001110101210112
422202312033210123
5141141422010011
65111251034535
7550366643261
oct124266174433
932201411715
1011322063131
114890011675
12223b89ba4b
1310b587b952
14795988431
15463eaa58b
hex2a2d8f91b

11322063131 has 4 divisors (see below), whose sum is σ = 11336787000. Its totient is φ = 11307339264.

The previous prime is 11322063127. The next prime is 11322063143. The reversal of 11322063131 is 13136022311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11322063131 - 22 = 11322063127 is a prime.

It is a super-2 number, since 2×113220631312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11322063097 and 11322063106.

It is not an unprimeable number, because it can be changed into a prime (11322063031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7360781 + ... + 7362318.

It is an arithmetic number, because the mean of its divisors is an integer number (2834196750).

Almost surely, 211322063131 is an apocalyptic number.

11322063131 is a deficient number, since it is larger than the sum of its proper divisors (14723869).

11322063131 is an equidigital number, since it uses as much as digits as its factorization.

11322063131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14723868.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 11322063131 its reverse (13136022311), we get a palindrome (24458085442).

The spelling of 11322063131 in words is "eleven billion, three hundred twenty-two million, sixty-three thousand, one hundred thirty-one".

Divisors: 1 769 14723099 11322063131