Base | Representation |
---|---|
bin | 10101000101101100… |
… | …01111100100011011 |
3 | 1002020001110101210112 |
4 | 22202312033210123 |
5 | 141141422010011 |
6 | 5111251034535 |
7 | 550366643261 |
oct | 124266174433 |
9 | 32201411715 |
10 | 11322063131 |
11 | 4890011675 |
12 | 223b89ba4b |
13 | 10b587b952 |
14 | 795988431 |
15 | 463eaa58b |
hex | 2a2d8f91b |
11322063131 has 4 divisors (see below), whose sum is σ = 11336787000. Its totient is φ = 11307339264.
The previous prime is 11322063127. The next prime is 11322063143. The reversal of 11322063131 is 13136022311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11322063131 - 22 = 11322063127 is a prime.
It is a super-2 number, since 2×113220631312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11322063097 and 11322063106.
It is not an unprimeable number, because it can be changed into a prime (11322063031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7360781 + ... + 7362318.
It is an arithmetic number, because the mean of its divisors is an integer number (2834196750).
Almost surely, 211322063131 is an apocalyptic number.
11322063131 is a deficient number, since it is larger than the sum of its proper divisors (14723869).
11322063131 is an equidigital number, since it uses as much as digits as its factorization.
11322063131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14723868.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 11322063131 its reverse (13136022311), we get a palindrome (24458085442).
The spelling of 11322063131 in words is "eleven billion, three hundred twenty-two million, sixty-three thousand, one hundred thirty-one".
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