11322210220123 has 4 divisors (see below), whose sum is σ = 12351502058328. Its totient is φ = 10292918381920.

The previous prime is 11322210220099. The next prime is 11322210220127. The reversal of 11322210220123 is 32102201222311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11322210220123 is a prime.

It is a super-3 number, since 3×11322210220123³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11322210220094 and 11322210220103.

It is not an unprimeable number, because it can be changed into a prime (11322210220127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 514645919086 + ... + 514645919107.

It is an arithmetic number, because the mean of its divisors is an integer number (3087875514582).

Almost surely, 2^{11322210220123} is an apocalyptic number.

11322210220123 is a deficient number, since it is larger than the sum of its proper divisors (1029291838205).

11322210220123 is a wasteful number, since it uses less digits than its factorization.

11322210220123 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1029291838204.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 11322210220123 its reverse (32102201222311), we get a palindrome (43424411442434).

The spelling of 11322210220123 in words is "eleven trillion, three hundred twenty-two billion, two hundred ten million, two hundred twenty thousand, one hundred twenty-three".