113231144114113 has 4 divisors (see below), whose sum is σ = 113231172248020. Its totient is φ = 113231115980208.

The previous prime is 113231144114107. The next prime is 113231144114129. The reversal of 113231144114113 is 311411441132311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 102256447269249 + 10974696844864 = 10112193^2 + 3312808^2 .

It is a cyclic number.

It is not a de Polignac number, because 113231144114113 - 2²¹ = 113231142016961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113231144114813) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6767178 + ... + 16500211.

It is an arithmetic number, because the mean of its divisors is an integer number (28307793062005).

Almost surely, 2^{113231144114113} is an apocalyptic number.

It is an amenable number.

113231144114113 is a deficient number, since it is larger than the sum of its proper divisors (28133907).

113231144114113 is an equidigital number, since it uses as much as digits as its factorization.

113231144114113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28133906.

The product of its digits is 3456, while the sum is 31.

Adding to 113231144114113 its reverse (311411441132311), we get a palindrome (424642585246424).

The spelling of 113231144114113 in words is "one hundred thirteen trillion, two hundred thirty-one billion, one hundred forty-four million, one hundred fourteen thousand, one hundred thirteen".