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11323200403 = 23886355547
BaseRepresentation
bin10101000101110101…
…00101001110010011
31002020010121011211201
422202322211032103
5141142214403103
65111331252031
7550412421034
oct124272451623
932203534751
1011323200403
114890719069
12224014a017
1310b5b894a8
14795ba2a8b
1546413251d
hex2a2ea5393

11323200403 has 8 divisors (see below), whose sum is σ = 11817059328. Its totient is φ = 10829470344.

The previous prime is 11323200401. The next prime is 11323200407. The reversal of 11323200403 is 30400232311.

11323200403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11323200403 - 21 = 11323200401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11323200401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 176076 + ... + 231622.

It is an arithmetic number, because the mean of its divisors is an integer number (1477132416).

Almost surely, 211323200403 is an apocalyptic number.

11323200403 is a deficient number, since it is larger than the sum of its proper divisors (493858925).

11323200403 is an equidigital number, since it uses as much as digits as its factorization.

11323200403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 64433.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 11323200403 its reverse (30400232311), we get a palindrome (41723432714).

The spelling of 11323200403 in words is "eleven billion, three hundred twenty-three million, two hundred thousand, four hundred three".

Divisors: 1 23 8863 55547 203849 1277581 492313061 11323200403