Base | Representation |
---|---|
bin | 1010010011000110001110… |
… | …0000000100101011010011 |
3 | 1111002111011111101120101011 |
4 | 2210301203200010223103 |
5 | 2441004410001110103 |
6 | 40025450244351351 |
7 | 2246034346450213 |
oct | 244614340045323 |
9 | 44074144346334 |
10 | 11323203144403 |
11 | 3676163a86007 |
12 | 132a6199a5557 |
13 | 641a0942a3b7 |
14 | 2b2090166243 |
15 | 149820e03d6d |
hex | a4c63804ad3 |
11323203144403 has 4 divisors (see below), whose sum is σ = 11323212201928. Its totient is φ = 11323194086880.
The previous prime is 11323203144401. The next prime is 11323203144481. The reversal of 11323203144403 is 30444130232311.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 11323203144403 - 21 = 11323203144401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11323203144401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2282001 + ... + 5277682.
It is an arithmetic number, because the mean of its divisors is an integer number (2830803050482).
Almost surely, 211323203144403 is an apocalyptic number.
11323203144403 is a deficient number, since it is larger than the sum of its proper divisors (9057525).
11323203144403 is an equidigital number, since it uses as much as digits as its factorization.
11323203144403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9057524.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 11323203144403 its reverse (30444130232311), we get a palindrome (41767333376714).
The spelling of 11323203144403 in words is "eleven trillion, three hundred twenty-three billion, two hundred three million, one hundred forty-four thousand, four hundred three".
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