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11323213403 = 82395314437
BaseRepresentation
bin10101000101110101…
…01000011001011011
31002020010121211200012
422202322220121123
5141142220312103
65111331432135
7550412503655
oct124272503133
932203554605
1011323213403
114890727907
12224015564b
1310b5b92398
14795ba76d5
154641362d8
hex2a2ea865b

11323213403 has 8 divisors (see below), whose sum is σ = 11349654048. Its totient is φ = 11296805184.

The previous prime is 11323213399. The next prime is 11323213427. The reversal of 11323213403 is 30431232311.

11323213403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11323213403 - 22 = 11323213399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11323213493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 777101 + ... + 791537.

It is an arithmetic number, because the mean of its divisors is an integer number (1418706756).

Almost surely, 211323213403 is an apocalyptic number.

11323213403 is a deficient number, since it is larger than the sum of its proper divisors (26440645).

11323213403 is an equidigital number, since it uses as much as digits as its factorization.

11323213403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16213.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 11323213403 its reverse (30431232311), we get a palindrome (41754445714).

The spelling of 11323213403 in words is "eleven billion, three hundred twenty-three million, two hundred thirteen thousand, four hundred three".

Divisors: 1 823 953 14437 784319 11881651 13758461 11323213403