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113233110121 = 211536649811
BaseRepresentation
bin110100101110100111…
…0000010010001101001
3101211021102001222200101
41221131032002101221
53323400134010441
6124004002305401
711116010361325
oct1513516022151
9354242058611
10113233110121
114402715864a
1219b41658261
13a8a728c211
1456a274a985
152e2ad86231
hex1a5d382469

113233110121 has 4 divisors (see below), whose sum is σ = 113769760144. Its totient is φ = 112696460100.

The previous prime is 113233110119. The next prime is 113233110143. The reversal of 113233110121 is 121011332311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113233110121 - 21 = 113233110119 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113233110191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 268324695 + ... + 268325116.

It is an arithmetic number, because the mean of its divisors is an integer number (28442440036).

Almost surely, 2113233110121 is an apocalyptic number.

It is an amenable number.

113233110121 is a deficient number, since it is larger than the sum of its proper divisors (536650023).

113233110121 is an equidigital number, since it uses as much as digits as its factorization.

113233110121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 536650022.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 113233110121 its reverse (121011332311), we get a palindrome (234244442432).

The spelling of 113233110121 in words is "one hundred thirteen billion, two hundred thirty-three million, one hundred ten thousand, one hundred twenty-one".

Divisors: 1 211 536649811 113233110121