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113233122001 = 448512524651
BaseRepresentation
bin110100101110100111…
…0000101001011010001
3101211021102002120222101
41221131032011023101
53323400134401001
6124004002440401
711116010441056
oct1513516051321
9354242076871
10113233122001
114402716656a
1219b41663101
13a8a729474c
1456a275102d
152e2ad89a01
hex1a5d3852d1

113233122001 has 4 divisors (see below), whose sum is σ = 113235691504. Its totient is φ = 113230552500.

The previous prime is 113233121993. The next prime is 113233122047. The reversal of 113233122001 is 100221332311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113233122001 - 23 = 113233121993 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 113233122001.

It is not an unprimeable number, because it can be changed into a prime (113233122601) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1217475 + ... + 1307176.

It is an arithmetic number, because the mean of its divisors is an integer number (28308922876).

Almost surely, 2113233122001 is an apocalyptic number.

It is an amenable number.

113233122001 is a deficient number, since it is larger than the sum of its proper divisors (2569503).

113233122001 is an equidigital number, since it uses as much as digits as its factorization.

113233122001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2569502.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 113233122001 its reverse (100221332311), we get a palindrome (213454454312).

The spelling of 113233122001 in words is "one hundred thirteen billion, two hundred thirty-three million, one hundred twenty-two thousand, one".

Divisors: 1 44851 2524651 113233122001