Base | Representation |
---|---|
bin | 10101000101111101… |
… | …00011010011011001 |
3 | 1002020012120001102112 |
4 | 22202332203103121 |
5 | 141143001203423 |
6 | 5111405442105 |
7 | 550424314133 |
oct | 124276432331 |
9 | 32205501375 |
10 | 11324241113 |
11 | 4891269a59 |
12 | 2240570335 |
13 | 10b61620b3 |
14 | 795d94053 |
15 | 46428aa78 |
hex | 2a2fa34d9 |
11324241113 has 4 divisors (see below), whose sum is σ = 11367299328. Its totient is φ = 11281182900.
The previous prime is 11324241101. The next prime is 11324241119. The reversal of 11324241113 is 31114242311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31114242311 = 547 ⋅56881613.
It is a cyclic number.
It is not a de Polignac number, because 11324241113 - 212 = 11324237017 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11324241119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21528713 + ... + 21529238.
It is an arithmetic number, because the mean of its divisors is an integer number (2841824832).
Almost surely, 211324241113 is an apocalyptic number.
It is an amenable number.
11324241113 is a deficient number, since it is larger than the sum of its proper divisors (43058215).
11324241113 is an equidigital number, since it uses as much as digits as its factorization.
11324241113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43058214.
The product of its digits is 576, while the sum is 23.
Adding to 11324241113 its reverse (31114242311), we get a palindrome (42438483424).
The spelling of 11324241113 in words is "eleven billion, three hundred twenty-four million, two hundred forty-one thousand, one hundred thirteen".
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