Base | Representation |
---|---|
bin | 10101000101111101… |
… | …10001101100011001 |
3 | 1002020012200001021122 |
4 | 22202332301230121 |
5 | 141143010100212 |
6 | 5111411015025 |
7 | 550424651030 |
oct | 124276615431 |
9 | 32205601248 |
10 | 11324300057 |
11 | 48912aa274 |
12 | 224059a475 |
13 | 10b6182b85 |
14 | 795dab717 |
15 | 46429d272 |
hex | 2a2fb1b19 |
11324300057 has 16 divisors (see below), whose sum is σ = 12982394880. Its totient is φ = 9676339152.
The previous prime is 11324300023. The next prime is 11324300069. The reversal of 11324300057 is 75000342311.
It is a cyclic number.
It is not a de Polignac number, because 11324300057 - 210 = 11324299033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11324299999 and 11324300035.
It is not an unprimeable number, because it can be changed into a prime (11324300087) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5488208 + ... + 5490270.
It is an arithmetic number, because the mean of its divisors is an integer number (811399680).
Almost surely, 211324300057 is an apocalyptic number.
It is an amenable number.
11324300057 is a deficient number, since it is larger than the sum of its proper divisors (1658094823).
11324300057 is a wasteful number, since it uses less digits than its factorization.
11324300057 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4132.
The product of its (nonzero) digits is 2520, while the sum is 26.
Adding to 11324300057 its reverse (75000342311), we get a palindrome (86324642368).
The spelling of 11324300057 in words is "eleven billion, three hundred twenty-four million, three hundred thousand, fifty-seven".
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