Base | Representation |
---|---|
bin | 110100101111000000… |
… | …1000111100101110001 |
3 | 101211022100021022211111 |
4 | 1221132001013211301 |
5 | 3323412101014413 |
6 | 124005201313321 |
7 | 11116232243425 |
oct | 1513601074561 |
9 | 354270238744 |
10 | 113246501233 |
11 | 44033774588 |
12 | 19b46035841 |
13 | a8a9c9a458 |
14 | 56a4434b85 |
15 | 2e2c12dd3d |
hex | 1a5e047971 |
113246501233 has 12 divisors (see below), whose sum is σ = 117074985984. Its totient is φ = 109539510600.
The previous prime is 113246501227. The next prime is 113246501257. The reversal of 113246501233 is 332105642311.
It is not a de Polignac number, because 113246501233 - 221 = 113244404081 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 113246501195 and 113246501204.
It is not an unprimeable number, because it can be changed into a prime (113246501273) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2000760 + ... + 2056582.
It is an arithmetic number, because the mean of its divisors is an integer number (9756248832).
Almost surely, 2113246501233 is an apocalyptic number.
It is an amenable number.
113246501233 is a deficient number, since it is larger than the sum of its proper divisors (3828484751).
113246501233 is an equidigital number, since it uses as much as digits as its factorization.
113246501233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57996 (or 57965 counting only the distinct ones).
The product of its (nonzero) digits is 12960, while the sum is 31.
The spelling of 113246501233 in words is "one hundred thirteen billion, two hundred forty-six million, five hundred one thousand, two hundred thirty-three".
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