Base | Representation |
---|---|
bin | 110100101111000111… |
… | …0100111100100110011 |
3 | 101211022120221010021012 |
4 | 1221132032213210303 |
5 | 3323414002240430 |
6 | 124005405221135 |
7 | 11116304313032 |
oct | 1513616474463 |
9 | 354276833235 |
10 | 113250040115 |
11 | 44035771383 |
12 | 19b472617ab |
13 | a8aa939174 |
14 | 56a4ab6719 |
15 | 2e2c5cc695 |
hex | 1a5e3a7933 |
113250040115 has 8 divisors (see below), whose sum is σ = 139573022640. Its totient is φ = 88151382432.
The previous prime is 113250040103. The next prime is 113250040133. The reversal of 113250040115 is 511040052311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 113250040115 - 230 = 112176298291 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 306081005 + ... + 306081374.
It is an arithmetic number, because the mean of its divisors is an integer number (17446627830).
Almost surely, 2113250040115 is an apocalyptic number.
113250040115 is a deficient number, since it is larger than the sum of its proper divisors (26322982525).
113250040115 is an equidigital number, since it uses as much as digits as its factorization.
113250040115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 612162421.
The product of its (nonzero) digits is 600, while the sum is 23.
Adding to 113250040115 its reverse (511040052311), we get a palindrome (624290092426).
The spelling of 113250040115 in words is "one hundred thirteen billion, two hundred fifty million, forty thousand, one hundred fifteen".
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