Base | Representation |
---|---|
bin | 10000011110101111001… |
… | …010011011000110111001 |
3 | 11000021012221001020012211 |
4 | 100132233022123012321 |
5 | 122023342334102441 |
6 | 2224134213535121 |
7 | 144551531615044 |
oct | 20365712330671 |
9 | 4007187036184 |
10 | 1132515144121 |
11 | 3a732a302029 |
12 | 1635a50444a1 |
13 | 82a4627291a |
14 | 3cb57985c5b |
15 | 1e6d52e7a81 |
hex | 107af29b1b9 |
1132515144121 has 4 divisors (see below), whose sum is σ = 1171567390500. Its totient is φ = 1093462897744.
The previous prime is 1132515144107. The next prime is 1132515144127. The reversal of 1132515144121 is 1214415152311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 766745409600 + 365769734521 = 875640^2 + 604789^2 .
It is a cyclic number.
It is not a de Polignac number, because 1132515144121 - 225 = 1132481589689 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1132515144127) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19526123146 + ... + 19526123203.
It is an arithmetic number, because the mean of its divisors is an integer number (292891847625).
Almost surely, 21132515144121 is an apocalyptic number.
It is an amenable number.
1132515144121 is a deficient number, since it is larger than the sum of its proper divisors (39052246379).
1132515144121 is an equidigital number, since it uses as much as digits as its factorization.
1132515144121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39052246378.
The product of its digits is 4800, while the sum is 31.
The spelling of 1132515144121 in words is "one trillion, one hundred thirty-two billion, five hundred fifteen million, one hundred forty-four thousand, one hundred twenty-one".
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