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1132530423241 = 7161790060463
BaseRepresentation
bin10000011110110000000…
…100101101010111001001
311000021020222210111020011
4100132300010231113021
5122023410242020431
62224135521231521
7144552105522430
oct20366004552711
94007228714204
101132530423241
113a73379984a8
121635aa1925a1
1382a49492319
143cb59a02117
151e6d6814cb1
hex107b012d5c9

1132530423241 has 4 divisors (see below), whose sum is σ = 1294320483712. Its totient is φ = 970740362772.

The previous prime is 1132530423173. The next prime is 1132530423319. The reversal of 1132530423241 is 1423240352311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1132530423241 - 27 = 1132530423113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1132530427241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80895030225 + ... + 80895030238.

It is an arithmetic number, because the mean of its divisors is an integer number (323580120928).

Almost surely, 21132530423241 is an apocalyptic number.

It is an amenable number.

1132530423241 is a deficient number, since it is larger than the sum of its proper divisors (161790060471).

1132530423241 is an equidigital number, since it uses as much as digits as its factorization.

1132530423241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 161790060470.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 1132530423241 its reverse (1423240352311), we get a palindrome (2555770775552).

The spelling of 1132530423241 in words is "one trillion, one hundred thirty-two billion, five hundred thirty million, four hundred twenty-three thousand, two hundred forty-one".

Divisors: 1 7 161790060463 1132530423241