Base | Representation |
---|---|
bin | 10101000110000110… |
… | …10111111000001001 |
3 | 1002020021221021012101 |
4 | 22203003113320021 |
5 | 141143312130113 |
6 | 5111452513401 |
7 | 550441130053 |
oct | 124303277011 |
9 | 32207837171 |
10 | 11325505033 |
11 | 4891a52617 |
12 | 2240a7b861 |
13 | 10b64b548b |
14 | 7962028d3 |
15 | 46443a2dd |
hex | 2a30d7e09 |
11325505033 has 4 divisors (see below), whose sum is σ = 11330902800. Its totient is φ = 11320107268.
The previous prime is 11325505019. The next prime is 11325505039. The reversal of 11325505033 is 33050552311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33050552311 = 7 ⋅4721507473.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11325505033 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11325504992 and 11325505010.
It is not an unprimeable number, because it can be changed into a prime (11325505039) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2695735 + ... + 2699932.
It is an arithmetic number, because the mean of its divisors is an integer number (2832725700).
Almost surely, 211325505033 is an apocalyptic number.
It is an amenable number.
11325505033 is a deficient number, since it is larger than the sum of its proper divisors (5397767).
11325505033 is an equidigital number, since it uses as much as digits as its factorization.
11325505033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5397766.
The product of its (nonzero) digits is 6750, while the sum is 28.
The spelling of 11325505033 in words is "eleven billion, three hundred twenty-five million, five hundred five thousand, thirty-three".
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