Base | Representation |
---|---|
bin | 10000011110110001011… |
… | …010110101010011011011 |
3 | 11000021022120021111221011 |
4 | 100132301122311103123 |
5 | 122023432032001110 |
6 | 2224142045154351 |
7 | 144552501443353 |
oct | 20366132652333 |
9 | 4007276244834 |
10 | 1132553000155 |
11 | 3a7349708905 |
12 | 1635b585b9b7 |
13 | 82a51068645 |
14 | 3cb5c9dbb63 |
15 | 1e6d87c448a |
hex | 107b16b54db |
1132553000155 has 16 divisors (see below), whose sum is σ = 1445347787040. Its totient is φ = 848989184512.
The previous prime is 1132553000129. The next prime is 1132553000167. The reversal of 1132553000155 is 5510003552311.
It is a cyclic number.
It is not a de Polignac number, because 1132553000155 - 25 = 1132553000123 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29329060 + ... + 29367649.
It is an arithmetic number, because the mean of its divisors is an integer number (90334236690).
Almost surely, 21132553000155 is an apocalyptic number.
1132553000155 is a deficient number, since it is larger than the sum of its proper divisors (312794786885).
1132553000155 is a wasteful number, since it uses less digits than its factorization.
1132553000155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58696958.
The product of its (nonzero) digits is 11250, while the sum is 31.
Adding to 1132553000155 its reverse (5510003552311), we get a palindrome (6642556552466).
The spelling of 1132553000155 in words is "one trillion, one hundred thirty-two billion, five hundred fifty-three million, one hundred fifty-five", and thus it is an aban number.
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