Base | Representation |
---|---|
bin | 110100101111010110… |
… | …0011111011100010011 |
3 | 101211100010122222101112 |
4 | 1221132230133130103 |
5 | 3323423003333443 |
6 | 124010245123535 |
7 | 11116431006665 |
oct | 1513654373423 |
9 | 354303588345 |
10 | 113257871123 |
11 | 4403a12a991 |
12 | 19b499b95ab |
13 | a8ac44b6b7 |
14 | 56a5b54535 |
15 | 2e2d127b18 |
hex | 1a5eb1f713 |
113257871123 has 4 divisors (see below), whose sum is σ = 113890596840. Its totient is φ = 112625145408.
The previous prime is 113257871081. The next prime is 113257871159. The reversal of 113257871123 is 321178752311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113257871123 - 214 = 113257854739 is a prime.
It is a super-2 number, since 2×1132578711232 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113257871173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 316362590 + ... + 316362947.
It is an arithmetic number, because the mean of its divisors is an integer number (28472649210).
Almost surely, 2113257871123 is an apocalyptic number.
113257871123 is a deficient number, since it is larger than the sum of its proper divisors (632725717).
113257871123 is an equidigital number, since it uses as much as digits as its factorization.
113257871123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 632725716.
The product of its digits is 70560, while the sum is 41.
The spelling of 113257871123 in words is "one hundred thirteen billion, two hundred fifty-seven million, eight hundred seventy-one thousand, one hundred twenty-three".
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