Base | Representation |
---|---|
bin | 11001110000001110001101… |
… | …100001000000101000111011 |
3 | 112212001000122120210021002221 |
4 | 121300032031201000220323 |
5 | 104321213112420204033 |
6 | 1040521111451104511 |
7 | 32600060134453141 |
oct | 3160161541005073 |
9 | 485030576707087 |
10 | 113264956803643 |
11 | 330a9442339067 |
12 | 10853610a42137 |
13 | 4b27abb7938c8 |
14 | 1dd80a5c27591 |
15 | d16434da112d |
hex | 67038d840a3b |
113264956803643 has 4 divisors (see below), whose sum is σ = 113296219561008. Its totient is φ = 113233694046280.
The previous prime is 113264956803641. The next prime is 113264956803653. The reversal of 113264956803643 is 346308659462311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113264956803643 - 21 = 113264956803641 is a prime.
It is a super-2 number, since 2×1132649568036432 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113264956803641) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15631373248 + ... + 15631380493.
It is an arithmetic number, because the mean of its divisors is an integer number (28324054890252).
Almost surely, 2113264956803643 is an apocalyptic number.
113264956803643 is a deficient number, since it is larger than the sum of its proper divisors (31262757365).
113264956803643 is an equidigital number, since it uses as much as digits as its factorization.
113264956803643 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31262757364.
The product of its (nonzero) digits is 67184640, while the sum is 61.
The spelling of 113264956803643 in words is "one hundred thirteen trillion, two hundred sixty-four billion, nine hundred fifty-six million, eight hundred three thousand, six hundred forty-three".
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