Base | Representation |
---|---|
bin | 11001110000101111000010… |
… | …110001101101001000111001 |
3 | 112212011101122110002211110102 |
4 | 121300233002301231020321 |
5 | 104322302312242023113 |
6 | 1040545221543525145 |
7 | 32602445553565031 |
oct | 3160570261551071 |
9 | 485141573084412 |
10 | 113300210111033 |
11 | 33112392971750 |
12 | 1085a40b1597b5 |
13 | 4b2b2193174ca |
14 | 1dd9a8bc308c1 |
15 | d172e9cba758 |
hex | 670bc2c6d239 |
113300210111033 has 8 divisors (see below), whose sum is σ = 123680333073216. Its totient is φ = 102933437792400.
The previous prime is 113300210111021. The next prime is 113300210111041. The reversal of 113300210111033 is 330111012003311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 113300210111033 - 214 = 113300210094649 is a prime.
It is a super-2 number, since 2×1133002101110332 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 113300210110996 and 113300210111014.
It is not an unprimeable number, because it can be changed into a prime (113300210011033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3337643138 + ... + 3337677083.
It is an arithmetic number, because the mean of its divisors is an integer number (15460041634152).
Almost surely, 2113300210111033 is an apocalyptic number.
It is an amenable number.
113300210111033 is a deficient number, since it is larger than the sum of its proper divisors (10380122962183).
113300210111033 is a wasteful number, since it uses less digits than its factorization.
113300210111033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6675321775.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 113300210111033 its reverse (330111012003311), we get a palindrome (443411222114344).
The spelling of 113300210111033 in words is "one hundred thirteen trillion, three hundred billion, two hundred ten million, one hundred eleven thousand, thirty-three".
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