Base | Representation |
---|---|
bin | 1010010011011111101010… |
… | …0110110010100111000011 |
3 | 1111010010210111101222121102 |
4 | 2210313322212302213003 |
5 | 2441112402001413243 |
6 | 40032540113045015 |
7 | 2246365533315041 |
oct | 244677246624703 |
9 | 44103714358542 |
10 | 11330033232323 |
11 | 3679049428173 |
12 | 132ba0525676b |
13 | 642557482040 |
14 | 2b253b2d3391 |
15 | 149ac08589b8 |
hex | a4dfa9b29c3 |
11330033232323 has 4 divisors (see below), whose sum is σ = 12201574250208. Its totient is φ = 10458492214440.
The previous prime is 11330033232307. The next prime is 11330033232341. The reversal of 11330033232323 is 32323233003311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11330033232323 - 24 = 11330033232307 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11330033232523) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 435770508923 + ... + 435770508948.
It is an arithmetic number, because the mean of its divisors is an integer number (3050393562552).
Almost surely, 211330033232323 is an apocalyptic number.
11330033232323 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
11330033232323 is a deficient number, since it is larger than the sum of its proper divisors (871541017885).
11330033232323 is an equidigital number, since it uses as much as digits as its factorization.
11330033232323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 871541017884.
The product of its (nonzero) digits is 17496, while the sum is 29.
Adding to 11330033232323 its reverse (32323233003311), we get a palindrome (43653266235634).
The spelling of 11330033232323 in words is "eleven trillion, three hundred thirty billion, thirty-three million, two hundred thirty-two thousand, three hundred twenty-three".
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