113301113131 has 4 divisors (see below), whose sum is σ = 113663097832. Its totient is φ = 112939128432.

The previous prime is 113301113129. The next prime is 113301113141. The reversal of 113301113131 is 131311103311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113301113131 - 2¹ = 113301113129 is a prime.

It is a super-2 number, since 2×113301113131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113301113099 and 113301113108.

It is not an unprimeable number, because it can be changed into a prime (113301113141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 180991881 + ... + 180992506.

It is an arithmetic number, because the mean of its divisors is an integer number (28415774458).

Almost surely, 2^113301113131 is an apocalyptic number.

113301113131 is a deficient number, since it is larger than the sum of its proper divisors (361984701).

113301113131 is an equidigital number, since it uses as much as digits as its factorization.

113301113131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 361984700.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 113301113131 its reverse (131311103311), we get a palindrome (244612216442).

The spelling of 113301113131 in words is "one hundred thirteen billion, three hundred one million, one hundred thirteen thousand, one hundred thirty-one".