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11330120131 = 113727838133
BaseRepresentation
bin10101000110101001…
…11110100111000011
31002020121121201220221
422203110332213003
5141201002321011
65112135443511
7550525301131
oct124324764703
932217551827
1011330120131
114894614a50
122242526597
1310b743ccc5
14796a84751
15464a4c971
hex2a353e9c3

11330120131 has 8 divisors (see below), whose sum is σ = 12694189104. Its totient is φ = 10021727520.

The previous prime is 11330120119. The next prime is 11330120141. The reversal of 11330120131 is 13102103311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11330120131 - 25 = 11330120099 is a prime.

It is a super-2 number, since 2×113301201312 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (11330120141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13918660 + ... + 13919473.

It is an arithmetic number, because the mean of its divisors is an integer number (1586773638).

Almost surely, 211330120131 is an apocalyptic number.

11330120131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

11330120131 is a deficient number, since it is larger than the sum of its proper divisors (1364068973).

11330120131 is a wasteful number, since it uses less digits than its factorization.

11330120131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27838181.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 11330120131 its reverse (13102103311), we get a palindrome (24432223442).

The spelling of 11330120131 in words is "eleven billion, three hundred thirty million, one hundred twenty thousand, one hundred thirty-one".

Divisors: 1 11 37 407 27838133 306219463 1030010921 11330120131