11330441322131 has 4 divisors (see below), whose sum is σ = 11330455452312. Its totient is φ = 11330427191952.

The previous prime is 11330441322113. The next prime is 11330441322149. The reversal of 11330441322131 is 13122314403311.

11330441322131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (11330441322113) and next prime (11330441322149).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11330441322131 is a prime.

It is a super-2 number, since 2×11330441322131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11330441322094 and 11330441322103.

It is not an unprimeable number, because it can be changed into a prime (11330441322331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5784986 + ... + 7491791.

It is an arithmetic number, because the mean of its divisors is an integer number (2832613863078).

Almost surely, 2^{11330441322131} is an apocalyptic number.

11330441322131 is a deficient number, since it is larger than the sum of its proper divisors (14130181).

11330441322131 is an equidigital number, since it uses as much as digits as its factorization.

11330441322131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14130180.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 11330441322131 its reverse (13122314403311), we get a palindrome (24452755725442).

The spelling of 11330441322131 in words is "eleven trillion, three hundred thirty billion, four hundred forty-one million, three hundred twenty-two thousand, one hundred thirty-one".