Base | Representation |
---|---|
bin | 11001110000110011110101… |
… | …011001011010111101000011 |
3 | 112212011212220221220021020111 |
4 | 121300303311121122331003 |
5 | 104322343331203203103 |
6 | 1040551432230452151 |
7 | 32603020210110325 |
oct | 3160636531327503 |
9 | 485155827807214 |
10 | 113305354350403 |
11 | 33114592736946 |
12 | 1085b405b04057 |
13 | 4b2b859008c27 |
14 | 1dda01911b615 |
15 | d174eb71486d |
hex | 670cf565af43 |
113305354350403 has 8 divisors (see below), whose sum is σ = 113339202217472. Its totient is φ = 113271507840456.
The previous prime is 113305354350379. The next prime is 113305354350473. The reversal of 113305354350403 is 304053453503311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113305354350403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113305354350473) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 181072876 + ... + 181697542.
It is an arithmetic number, because the mean of its divisors is an integer number (14167400277184).
Almost surely, 2113305354350403 is an apocalyptic number.
113305354350403 is a deficient number, since it is larger than the sum of its proper divisors (33847867069).
113305354350403 is an equidigital number, since it uses as much as digits as its factorization.
113305354350403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 678561.
The product of its (nonzero) digits is 486000, while the sum is 40.
The spelling of 113305354350403 in words is "one hundred thirteen trillion, three hundred five billion, three hundred fifty-four million, three hundred fifty thousand, four hundred three".
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