Search a number
-
+
11331010113 = 33777003371
BaseRepresentation
bin10101000110110000…
…10111111001000001
31002020200021221202020
422203120113321001
5141201214310423
65112210512053
7550535665623
oct124330277101
932220257666
1011331010113
114895072675
122242895629
1310b7692117
14796c36c13
15464b764e3
hex2a3617e41

11331010113 has 4 divisors (see below), whose sum is σ = 15108013488. Its totient is φ = 7554006740.

The previous prime is 11331010049. The next prime is 11331010127. The reversal of 11331010113 is 31101013311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11331010113 - 26 = 11331010049 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11331010092 and 11331010101.

It is not an unprimeable number, because it can be changed into a prime (11331010133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1888501683 + ... + 1888501688.

It is an arithmetic number, because the mean of its divisors is an integer number (3777003372).

Almost surely, 211331010113 is an apocalyptic number.

It is an amenable number.

11331010113 is a deficient number, since it is larger than the sum of its proper divisors (3777003375).

11331010113 is an equidigital number, since it uses as much as digits as its factorization.

11331010113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3777003374.

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 11331010113 its reverse (31101013311), we get a palindrome (42432023424).

The spelling of 11331010113 in words is "eleven billion, three hundred thirty-one million, ten thousand, one hundred thirteen".

Divisors: 1 3 3777003371 11331010113