1133111140121 has 4 divisors (see below), whose sum is σ = 1151686732644. Its totient is φ = 1114535547600.

The previous prime is 1133111140103. The next prime is 1133111140129. The reversal of 1133111140121 is 1210411113311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 421726854025 + 711384286096 = 649405^2 + 843436^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1133111140121 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1133111140093 and 1133111140102.

It is not an unprimeable number, because it can be changed into a prime (1133111140129) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9287796170 + ... + 9287796291.

It is an arithmetic number, because the mean of its divisors is an integer number (287921683161).

Almost surely, 2^{1133111140121} is an apocalyptic number.

It is an amenable number.

1133111140121 is a deficient number, since it is larger than the sum of its proper divisors (18575592523).

1133111140121 is an equidigital number, since it uses as much as digits as its factorization.

1133111140121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18575592522.

The product of its (nonzero) digits is 72, while the sum is 20.

Adding to 1133111140121 its reverse (1210411113311), we get a palindrome (2343522253432).

The spelling of 1133111140121 in words is "one trillion, one hundred thirty-three billion, one hundred eleven million, one hundred forty thousand, one hundred twenty-one".