Base | Representation |
---|---|
bin | 1010010011100011101110… |
… | …0000001001111110000001 |
3 | 1111010020121101010201120212 |
4 | 2210320323200021332001 |
5 | 2441122114213341113 |
6 | 40033240125243505 |
7 | 2246434523636645 |
oct | 244707340117601 |
9 | 44106541121525 |
10 | 11331122012033 |
11 | 3679557a7950a |
12 | 1330069a03595 |
13 | 64269bc048a5 |
14 | 2b2601b50c25 |
15 | 149b362250a8 |
hex | a4e3b809f81 |
11331122012033 has 8 divisors (see below), whose sum is σ = 11403861947520. Its totient is φ = 11258389256400.
The previous prime is 11331122011981. The next prime is 11331122012107. The reversal of 11331122012033 is 33021022113311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11331122012033 - 236 = 11262402535297 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11331022012033) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1389608 + ... + 4959158.
It is an arithmetic number, because the mean of its divisors is an integer number (1425482743440).
Almost surely, 211331122012033 is an apocalyptic number.
It is an amenable number.
11331122012033 is a deficient number, since it is larger than the sum of its proper divisors (72739935487).
11331122012033 is a wasteful number, since it uses less digits than its factorization.
11331122012033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3589927.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 11331122012033 its reverse (33021022113311), we get a palindrome (44352144125344).
The spelling of 11331122012033 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-two million, twelve thousand, thirty-three".
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