Base | Representation |
---|---|
bin | 10101000110110001… |
… | …10101011011101001 |
3 | 1002020200112002201201 |
4 | 22203120311123221 |
5 | 141201232143423 |
6 | 5112213244201 |
7 | 550540011451 |
oct | 124330653351 |
9 | 32220462651 |
10 | 11331131113 |
11 | 4895145575 |
12 | 2242933661 |
13 | 10b7705213 |
14 | 796c68d61 |
15 | 464b9c2ad |
hex | 2a36356e9 |
11331131113 has 4 divisors (see below), whose sum is σ = 11347869060. Its totient is φ = 11314393168.
The previous prime is 11331131107. The next prime is 11331131167. The reversal of 11331131113 is 31113113311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 8684748864 + 2646382249 = 93192^2 + 51443^2 .
It is a cyclic number.
It is not a de Polignac number, because 11331131113 - 217 = 11331000041 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11331131813) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8367958 + ... + 8369311.
It is an arithmetic number, because the mean of its divisors is an integer number (2836967265).
Almost surely, 211331131113 is an apocalyptic number.
It is an amenable number.
11331131113 is a deficient number, since it is larger than the sum of its proper divisors (16737947).
11331131113 is an equidigital number, since it uses as much as digits as its factorization.
11331131113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16737946.
The product of its digits is 81, while the sum is 19.
Adding to 11331131113 its reverse (31113113311), we get a palindrome (42444244424).
The spelling of 11331131113 in words is "eleven billion, three hundred thirty-one million, one hundred thirty-one thousand, one hundred thirteen".
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