Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …0011101000001110011011 |
3 | 1111010020122000122011101011 |
4 | 2210320330003220032123 |
5 | 2441122124103423003 |
6 | 40033241100434351 |
7 | 2246434665656440 |
oct | 244707403501633 |
9 | 44106560564334 |
10 | 11331131311003 |
11 | 367956224aa09 |
12 | 1330070b489b7 |
13 | 6426a0b0c33a |
14 | 2b26030919c7 |
15 | 149b36e6046d |
hex | a4e3c0e839b |
11331131311003 has 4 divisors (see below), whose sum is σ = 12949864355440. Its totient is φ = 9712398266568.
The previous prime is 11331131310991. The next prime is 11331131311007. The reversal of 11331131311003 is 30011313113311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11331131311003 - 233 = 11322541376411 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11331131311007) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 809366522208 + ... + 809366522221.
It is an arithmetic number, because the mean of its divisors is an integer number (3237466088860).
Almost surely, 211331131311003 is an apocalyptic number.
11331131311003 is a deficient number, since it is larger than the sum of its proper divisors (1618733044437).
11331131311003 is an equidigital number, since it uses as much as digits as its factorization.
11331131311003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1618733044436.
The product of its (nonzero) digits is 243, while the sum is 22.
Adding to 11331131311003 its reverse (30011313113311), we get a palindrome (41342444424314).
The spelling of 11331131311003 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, three hundred eleven thousand, three".
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