Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …0110010000100001001011 |
3 | 1111010020122001221011221211 |
4 | 2210320330012100201023 |
5 | 2441122124243002311 |
6 | 40033241123313551 |
7 | 2246435004560233 |
oct | 244707406204113 |
9 | 44106561834854 |
10 | 11331132000331 |
11 | 3679562680900 |
12 | 133007121b8b7 |
13 | 6426a0cc1020 |
14 | 2b26031d0cc3 |
15 | 149b37049821 |
hex | a4e3c19084b |
11331132000331 has 12 divisors (see below), whose sum is σ = 13412948370976. Its totient is φ = 9508642236720.
The previous prime is 11331132000281. The next prime is 11331132000371. The reversal of 11331132000331 is 13300023113311.
It is not a de Polignac number, because 11331132000331 - 215 = 11331131967563 is a prime.
It is a super-2 number, since 2×113311320003312 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (11331132000371) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3601756851 + ... + 3601759996.
Almost surely, 211331132000331 is an apocalyptic number.
11331132000331 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
11331132000331 is a deficient number, since it is larger than the sum of its proper divisors (2081816370645).
11331132000331 is a wasteful number, since it uses less digits than its factorization.
11331132000331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7203516882 (or 7203516871 counting only the distinct ones).
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 11331132000331 its reverse (13300023113311), we get a palindrome (24631155113642).
The spelling of 11331132000331 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-two million, three hundred thirty-one", and thus it is an aban number.
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