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11331132000331 = 112137203516847
BaseRepresentation
bin1010010011100011110000…
…0110010000100001001011
31111010020122001221011221211
42210320330012100201023
52441122124243002311
640033241123313551
72246435004560233
oct244707406204113
944106561834854
1011331132000331
113679562680900
12133007121b8b7
136426a0cc1020
142b26031d0cc3
15149b37049821
hexa4e3c19084b

11331132000331 has 12 divisors (see below), whose sum is σ = 13412948370976. Its totient is φ = 9508642236720.

The previous prime is 11331132000281. The next prime is 11331132000371. The reversal of 11331132000331 is 13300023113311.

It is not a de Polignac number, because 11331132000331 - 215 = 11331131967563 is a prime.

It is a super-2 number, since 2×113311320003312 (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (11331132000371) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3601756851 + ... + 3601759996.

Almost surely, 211331132000331 is an apocalyptic number.

11331132000331 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

11331132000331 is a deficient number, since it is larger than the sum of its proper divisors (2081816370645).

11331132000331 is a wasteful number, since it uses less digits than its factorization.

11331132000331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7203516882 (or 7203516871 counting only the distinct ones).

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 11331132000331 its reverse (13300023113311), we get a palindrome (24631155113642).

The spelling of 11331132000331 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-two million, three hundred thirty-one", and thus it is an aban number.

Divisors: 1 11 13 121 143 1573 7203516847 79238685317 93645719011 871625538487 1030102909121 11331132000331