11331132003131 has 4 divisors (see below), whose sum is σ = 11335820103192. Its totient is φ = 11326443903072.

The previous prime is 11331132003049. The next prime is 11331132003277. The reversal of 11331132003131 is 13130023113311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11331132003131 - 2¹⁰ = 11331132002107 is a prime.

It is a super-2 number, since 2×11331132003131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11331132003097 and 11331132003106.

It is not an unprimeable number, because it can be changed into a prime (11331132023131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2344046405 + ... + 2344051238.

It is an arithmetic number, because the mean of its divisors is an integer number (2833955025798).

Almost surely, 2^{11331132003131} is an apocalyptic number.

11331132003131 is a deficient number, since it is larger than the sum of its proper divisors (4688100061).

11331132003131 is an equidigital number, since it uses as much as digits as its factorization.

11331132003131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4688100060.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 11331132003131 its reverse (13130023113311), we get a palindrome (24461155116442).

The spelling of 11331132003131 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-two million, three thousand, one hundred thirty-one".