1133121103113 has 4 divisors (see below), whose sum is σ = 1510828137488. Its totient is φ = 755414068740.

The previous prime is 1133121103111. The next prime is 1133121103133. The reversal of 1133121103113 is 3113011213311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1133121103113 - 2¹ = 1133121103111 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1133121103113.

It is not an unprimeable number, because it can be changed into a prime (1133121103111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188853517183 + ... + 188853517188.

It is an arithmetic number, because the mean of its divisors is an integer number (377707034372).

Almost surely, 2^{1133121103113} is an apocalyptic number.

It is an amenable number.

1133121103113 is a deficient number, since it is larger than the sum of its proper divisors (377707034375).

1133121103113 is an equidigital number, since it uses as much as digits as its factorization.

1133121103113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 377707034374.

The product of its (nonzero) digits is 162, while the sum is 21.

Adding to 1133121103113 its reverse (3113011213311), we get a palindrome (4246132316424).

The spelling of 1133121103113 in words is "one trillion, one hundred thirty-three billion, one hundred twenty-one million, one hundred three thousand, one hundred thirteen".