Base | Representation |
---|---|
bin | 10101000110110010… |
… | …11111101111110001 |
3 | 1002020200211220110222 |
4 | 22203121133233301 |
5 | 141201303220213 |
6 | 5112221102425 |
7 | 550541332661 |
oct | 124331375761 |
9 | 32220756428 |
10 | 11331304433 |
11 | 4895253809 |
12 | 22429b7a15 |
13 | 10b7766087 |
14 | 796cb21a1 |
15 | 464bd3808 |
hex | 2a365fbf1 |
11331304433 has 4 divisors (see below), whose sum is σ = 11443495668. Its totient is φ = 11219113200.
The previous prime is 11331304421. The next prime is 11331304447. The reversal of 11331304433 is 33440313311.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33440313311 = 101 ⋅331092211.
It can be written as a sum of positive squares in 2 ways, for example, as 5809031089 + 5522273344 = 76217^2 + 74312^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11331304433 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11331306433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56095466 + ... + 56095667.
It is an arithmetic number, because the mean of its divisors is an integer number (2860873917).
Almost surely, 211331304433 is an apocalyptic number.
It is an amenable number.
11331304433 is a deficient number, since it is larger than the sum of its proper divisors (112191235).
11331304433 is a wasteful number, since it uses less digits than its factorization.
11331304433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 112191234.
The product of its (nonzero) digits is 3888, while the sum is 26.
Adding to 11331304433 its reverse (33440313311), we get a palindrome (44771617744).
The spelling of 11331304433 in words is "eleven billion, three hundred thirty-one million, three hundred four thousand, four hundred thirty-three".
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