Base | Representation |
---|---|
bin | 1010010011100100011101… |
… | …0111101000001010011011 |
3 | 1111010021010020202121001111 |
4 | 2210321013113220022123 |
5 | 2441123021200244003 |
6 | 40033312000401151 |
7 | 2246442462120046 |
oct | 244710727501233 |
9 | 44107106677044 |
10 | 11331321103003 |
11 | 367964a3a0500 |
12 | 13301046161b7 |
13 | 6427012311b5 |
14 | 2b2620377c5d |
15 | 149b4894ee6d |
hex | a4e475e829b |
11331321103003 has 6 divisors (see below), whose sum is σ = 12455088485252. Its totient is φ = 10301201002620.
The previous prime is 11331321103001. The next prime is 11331321103007. The reversal of 11331321103003 is 30030112313311.
11331321103003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11331321103003 - 21 = 11331321103001 is a prime.
It is a super-2 number, since 2×113313211030032 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11331321103001) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 46823640801 + ... + 46823641042.
Almost surely, 211331321103003 is an apocalyptic number.
11331321103003 is a deficient number, since it is larger than the sum of its proper divisors (1123767382249).
11331321103003 is an equidigital number, since it uses as much as digits as its factorization.
11331321103003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 93647281865 (or 93647281854 counting only the distinct ones).
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 11331321103003 its reverse (30030112313311), we get a palindrome (41361433416314).
The spelling of 11331321103003 in words is "eleven trillion, three hundred thirty-one billion, three hundred twenty-one million, one hundred three thousand, three".
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