Base | Representation |
---|---|
bin | 10000011111010111101… |
… | …011101011001100011011 |
3 | 11000022222022012220202020 |
4 | 100133113223223030123 |
5 | 122031240401340103 |
6 | 2224325500305523 |
7 | 144604425066456 |
oct | 20372753531433 |
9 | 4008868186666 |
10 | 1133194949403 |
11 | 3a7649008880 |
12 | 1637548422a3 |
13 | 82b2406107a |
14 | 3cbbdd8449d |
15 | 1e724d2b753 |
hex | 107d7aeb31b |
1133194949403 has 8 divisors (see below), whose sum is σ = 1648283562816. Its totient is φ = 686784817800.
The previous prime is 1133194949357. The next prime is 1133194949407. The reversal of 1133194949403 is 3049494913311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1133194949403 - 212 = 1133194945307 is a prime.
It is a Smith number, since the sum of its digits (51) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is not an unprimeable number, because it can be changed into a prime (1133194949407) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17169620413 + ... + 17169620478.
It is an arithmetic number, because the mean of its divisors is an integer number (206035445352).
Almost surely, 21133194949403 is an apocalyptic number.
1133194949403 is a deficient number, since it is larger than the sum of its proper divisors (515088613413).
1133194949403 is a wasteful number, since it uses less digits than its factorization.
1133194949403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34339240905.
The product of its (nonzero) digits is 1259712, while the sum is 51.
The spelling of 1133194949403 in words is "one trillion, one hundred thirty-three billion, one hundred ninety-four million, nine hundred forty-nine thousand, four hundred three".
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