Base | Representation |
---|---|
bin | 10101000110111000… |
… | …01001100111001001 |
3 | 1002020202011020220011 |
4 | 22203130021213021 |
5 | 141201443001301 |
6 | 5112244031521 |
7 | 550550261314 |
oct | 124334114711 |
9 | 32222136804 |
10 | 11332000201 |
11 | 4895689525 |
12 | 22430925a1 |
13 | 10b794a982 |
14 | 79701397b |
15 | 464cbea51 |
hex | 2a37099c9 |
11332000201 has 4 divisors (see below), whose sum is σ = 11332686592. Its totient is φ = 11331313812.
The previous prime is 11332000181. The next prime is 11332000213. The reversal of 11332000201 is 10200023311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10200023311 = 373 ⋅27345907.
It is a cyclic number.
It is not a de Polignac number, because 11332000201 - 215 = 11331967433 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11332000261) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 317805 + ... + 351658.
It is an arithmetic number, because the mean of its divisors is an integer number (2833171648).
Almost surely, 211332000201 is an apocalyptic number.
It is an amenable number.
11332000201 is a deficient number, since it is larger than the sum of its proper divisors (686391).
11332000201 is an equidigital number, since it uses as much as digits as its factorization.
11332000201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 686390.
The product of its (nonzero) digits is 36, while the sum is 13.
Adding to 11332000201 its reverse (10200023311), we get a palindrome (21532023512).
The spelling of 11332000201 in words is "eleven billion, three hundred thirty-two million, two hundred one", and thus it is an aban number.
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