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1133210300113 = 2283594962407
BaseRepresentation
bin10000011111011000100…
…110001110111011010001
311000100000101002210222001
4100133120212032323101
5122031303314100423
62224331205314001
7144605002422643
oct20373046167321
94010011083861
101133210300113
113a7656743011
12163759a05901
1382b272a7228
143cbc201c893
151e72635ecad
hex107d898eed1

1133210300113 has 4 divisors (see below), whose sum is σ = 1133215490880. Its totient is φ = 1133205109348.

The previous prime is 1133210300111. The next prime is 1133210300143. The reversal of 1133210300113 is 3110030123311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1133210300113 - 21 = 1133210300111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1133210300111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2252845 + ... + 2709562.

It is an arithmetic number, because the mean of its divisors is an integer number (283303872720).

Almost surely, 21133210300113 is an apocalyptic number.

It is an amenable number.

1133210300113 is a deficient number, since it is larger than the sum of its proper divisors (5190767).

1133210300113 is an equidigital number, since it uses as much as digits as its factorization.

1133210300113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5190766.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1133210300113 its reverse (3110030123311), we get a palindrome (4243240423424).

The spelling of 1133210300113 in words is "one trillion, one hundred thirty-three billion, two hundred ten million, three hundred thousand, one hundred thirteen".

Divisors: 1 228359 4962407 1133210300113