1133401204441 has 4 divisors (see below), whose sum is σ = 1236437677584. Its totient is φ = 1030364731300.

The previous prime is 1133401204433. The next prime is 1133401204469. The reversal of 1133401204441 is 1444021043311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1133401204441 - 2³ = 1133401204433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1133401204841) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51518236555 + ... + 51518236576.

It is an arithmetic number, because the mean of its divisors is an integer number (309109419396).

Almost surely, 2^{1133401204441} is an apocalyptic number.

1133401204441 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1133401204441 is a deficient number, since it is larger than the sum of its proper divisors (103036473143).

1133401204441 is a wasteful number, since it uses less digits than its factorization.

1133401204441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 103036473142.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 1133401204441 its reverse (1444021043311), we get a palindrome (2577422247752).

The spelling of 1133401204441 in words is "one trillion, one hundred thirty-three billion, four hundred one million, two hundred four thousand, four hundred forty-one".