Base | Representation |
---|---|
bin | 11001110001010101111111… |
… | …011100110011011010100011 |
3 | 112212022101120222001001110001 |
4 | 121301111333130303122203 |
5 | 104323443434214344303 |
6 | 1041020335422120431 |
7 | 32605456112002444 |
oct | 3161257734633243 |
9 | 485271528031401 |
10 | 113342030231203 |
11 | 331290a3276a34 |
12 | 10866540720117 |
13 | 4b321524b2b47 |
14 | 1ddbad80312cb |
15 | d1844648231d |
hex | 67157f7336a3 |
113342030231203 has 4 divisors (see below), whose sum is σ = 113997186475488. Its totient is φ = 112686873986920.
The previous prime is 113342030231167. The next prime is 113342030231219. The reversal of 113342030231203 is 302132030243311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113342030231203 - 221 = 113342028134051 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113342030231303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 327578121883 + ... + 327578122228.
It is an arithmetic number, because the mean of its divisors is an integer number (28499296618872).
Almost surely, 2113342030231203 is an apocalyptic number.
113342030231203 is a deficient number, since it is larger than the sum of its proper divisors (655156244285).
113342030231203 is an equidigital number, since it uses as much as digits as its factorization.
113342030231203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 655156244284.
The product of its (nonzero) digits is 7776, while the sum is 28.
Adding to 113342030231203 its reverse (302132030243311), we get a palindrome (415474060474514).
The spelling of 113342030231203 in words is "one hundred thirteen trillion, three hundred forty-two billion, thirty million, two hundred thirty-one thousand, two hundred three".
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