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113366551363 = 138720503951
BaseRepresentation
bin110100110010100101…
…1000100101101000011
3101211121201011111122121
41221211023010231003
53324133314120423
6124025130345111
711122220534002
oct1514513045503
9354551144577
10113366551363
114409550aa6a
1219b7a28b197
13a8c8b11130
1456b6364c39
152e3794445d
hex1a652c4b43

113366551363 has 4 divisors (see below), whose sum is σ = 122087055328. Its totient is φ = 104646047400.

The previous prime is 113366551297. The next prime is 113366551379. The reversal of 113366551363 is 363155663311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113366551363 - 217 = 113366420291 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113366551393) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4360251963 + ... + 4360251988.

It is an arithmetic number, because the mean of its divisors is an integer number (30521763832).

Almost surely, 2113366551363 is an apocalyptic number.

113366551363 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

113366551363 is a deficient number, since it is larger than the sum of its proper divisors (8720503965).

113366551363 is an equidigital number, since it uses as much as digits as its factorization.

113366551363 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8720503964.

The product of its digits is 437400, while the sum is 43.

The spelling of 113366551363 in words is "one hundred thirteen billion, three hundred sixty-six million, five hundred fifty-one thousand, three hundred sixty-three".

Divisors: 1 13 8720503951 113366551363