Base | Representation |
---|---|
bin | 110100110010100101… |
… | …1000100101101000011 |
3 | 101211121201011111122121 |
4 | 1221211023010231003 |
5 | 3324133314120423 |
6 | 124025130345111 |
7 | 11122220534002 |
oct | 1514513045503 |
9 | 354551144577 |
10 | 113366551363 |
11 | 4409550aa6a |
12 | 19b7a28b197 |
13 | a8c8b11130 |
14 | 56b6364c39 |
15 | 2e3794445d |
hex | 1a652c4b43 |
113366551363 has 4 divisors (see below), whose sum is σ = 122087055328. Its totient is φ = 104646047400.
The previous prime is 113366551297. The next prime is 113366551379. The reversal of 113366551363 is 363155663311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113366551363 - 217 = 113366420291 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113366551393) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4360251963 + ... + 4360251988.
It is an arithmetic number, because the mean of its divisors is an integer number (30521763832).
Almost surely, 2113366551363 is an apocalyptic number.
113366551363 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
113366551363 is a deficient number, since it is larger than the sum of its proper divisors (8720503965).
113366551363 is an equidigital number, since it uses as much as digits as its factorization.
113366551363 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8720503964.
The product of its digits is 437400, while the sum is 43.
The spelling of 113366551363 in words is "one hundred thirteen billion, three hundred sixty-six million, five hundred fifty-one thousand, three hundred sixty-three".
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