Base | Representation |
---|---|
bin | 10101000111110101… |
… | …01011000111010011 |
3 | 1002021022012202221201 |
4 | 22203322223013103 |
5 | 141211020023442 |
6 | 5113131332031 |
7 | 551005265404 |
oct | 124372530723 |
9 | 32238182851 |
10 | 11340001747 |
11 | 489a154178 |
12 | 22458b1017 |
13 | 10b94bca09 |
14 | 7980d79ab |
15 | 4658507b7 |
hex | 2a3eab1d3 |
11340001747 has 4 divisors (see below), whose sum is σ = 11731036320. Its totient is φ = 10948967176.
The previous prime is 11340001727. The next prime is 11340001763. The reversal of 11340001747 is 74710004311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11340001747 - 231 = 9192518099 is a prime.
It is a super-3 number, since 3×113400017473 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11340001727) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 195517243 + ... + 195517300.
It is an arithmetic number, because the mean of its divisors is an integer number (2932759080).
Almost surely, 211340001747 is an apocalyptic number.
11340001747 is a deficient number, since it is larger than the sum of its proper divisors (391034573).
11340001747 is an equidigital number, since it uses as much as digits as its factorization.
11340001747 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 391034572.
The product of its (nonzero) digits is 2352, while the sum is 28.
The spelling of 11340001747 in words is "eleven billion, three hundred forty million, one thousand, seven hundred forty-seven".
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