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113400042233 = 439258314447
BaseRepresentation
bin110100110011100101…
…0110101001011111001
3101211201001012000111012
41221213022311023321
53324220402322413
6124032324243305
711123105312012
oct1514712651371
9354631160435
10113400042233
1144102405175
1219b89540535
13a902a3900a
1456ba9a2009
152e3a85c7a8
hex1a672b52f9

113400042233 has 4 divisors (see below), whose sum is σ = 113658357120. Its totient is φ = 113141727348.

The previous prime is 113400042199. The next prime is 113400042251. The reversal of 113400042233 is 332240004311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113400042233 - 232 = 109105074937 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113400042199 and 113400042208.

It is not an unprimeable number, because it can be changed into a prime (113400042293) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 129156785 + ... + 129157662.

It is an arithmetic number, because the mean of its divisors is an integer number (28414589280).

Almost surely, 2113400042233 is an apocalyptic number.

It is an amenable number.

113400042233 is a deficient number, since it is larger than the sum of its proper divisors (258314887).

113400042233 is an equidigital number, since it uses as much as digits as its factorization.

113400042233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 258314886.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 113400042233 its reverse (332240004311), we get a palindrome (445640046544).

The spelling of 113400042233 in words is "one hundred thirteen billion, four hundred million, forty-two thousand, two hundred thirty-three".

Divisors: 1 439 258314447 113400042233