11340013432331 has 4 divisors (see below), whose sum is σ = 11341794499392. Its totient is φ = 11338232365272.

The previous prime is 11340013432213. The next prime is 11340013432343. The reversal of 11340013432331 is 13323431004311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11340013432331 is a prime.

It is a super-2 number, since 2×11340013432331² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11340013432294 and 11340013432303.

It is not an unprimeable number, because it can be changed into a prime (11340013432361) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 890523980 + ... + 890536713.

It is an arithmetic number, because the mean of its divisors is an integer number (2835448624848).

Almost surely, 2^{11340013432331} is an apocalyptic number.

11340013432331 is a deficient number, since it is larger than the sum of its proper divisors (1781067061).

11340013432331 is an equidigital number, since it uses as much as digits as its factorization.

11340013432331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1781067060.

The product of its (nonzero) digits is 7776, while the sum is 29.

Adding to 11340013432331 its reverse (13323431004311), we get a palindrome (24663444436642).

The spelling of 11340013432331 in words is "eleven trillion, three hundred forty billion, thirteen million, four hundred thirty-two thousand, three hundred thirty-one".